Publication: Tek Kristal X-Işını Kırınım Yöntemi ile C15H13NO2, C15H13NO2, C19H15NO2 Kristallerinin Yapı Analizleri
Abstract
ÖZET Bu çalışmada schiff bazı olan l-{4-[(2,3-Dihidroksi-benziliden)-amino]-fenil}- etanon (C15H13NO3), l-{4-[(2-Hidroksi-benziliden)-amino]-fenil}-etanon (C15H13NO2) ve l-[(4-Asetil-fenilamino)-metilen]-lH-naftalen-2-one (C19H15NO2) kristallerinin yapı analizleri, tek kristal x-ışınlan yöntemiyle yapılmıştır. Atomik parametrelerin arıtımı tam-matris en küçük kareler ve Fark-Fourier yöntemleri kullanılarak yapılmıştır. C15H13NO3, Monoklinik, P2,/c, a=10.0014(ll)Â, b=14.4188(14)Â, c=8.8212(10)Â, a= 90°, (3=104.413(9)°, y=90°, V=1232.1(2)Â3, Z=4, Dx=1.376gr/cm3, X(MoKa)=0.71073Â, u^O.lOmm'1, T=293(2)°K, R=0.035, R<ö=0.086, S=0.092, F(000)=224. C15H13NO3 kristali düzlemsel değildir ve kristali oluşturan iki aromatik halka düzlemleri arasındaki açı 53.97(7)°'dir. Schiff bazların karakteristik özelliği olan C=N çift bağının uzunluğu 1.271(2)Â olarak belirlenmiş olup, bu değerin literatürle uyumlu olduğu görülmüştür. Kristal yapıda salisilaldehitlerde yaygın olarak görülen fenol-imin taoutomerik yapı gözlenmiş ve molekül içi O-H...N ve 0-H...0 tipi, moleküller arası 0-H...0 tipi hidrojen bağları tespit edilmiştir. CI5Hı3N02, Monoklinik, P2ı/c, a=14.7692(ll)Â, b=7.4051(5)Â, c=11.5752(14)Â,a= 90°, p=l 06.898(8)°, y=90°, V=l 211. 29(1 9)Â3, Z=4, Dx=1.312gr/cm3, X(MoKa)=0.71073Â, ^=0.09mm4, T=293(2)°K, R=0.038, Ro)=0.100, S=0.097, F(000)=215. C15H13NO2 kristalinde, C=N çift bağıyla birbirine bağlı iki aromatik halka düzlemi arasındaki açı 35.60(5)°'dir. C=N bağı uzunluğu 1.277(2)Â çift bağ uzunluğu için uygundur. Bu kristal yapı için de salisilaldehitlerde yaygın olarak görülen fenol- imin tautomerik yapı gözlenmiş olup sadece bir tane, bağ uzunluğu 2.5941(15)Â olan molekül içi O-H...N tipi kuvvetli hidrojen bağı tespit edilmiştir. C19H,5N02, Monoklinik, P2ı/c, a=6.7815(14)Â, b=14.0948(12)Â, o=l 5.0855(1 0)Â, a=90°, p=90.050(5)°, y=90°, V=1441.93(2)Â3, Z=4, Dx=1.33gr/cm3, X(MoKa)=0.71073Â, M.=0.087mm'1, T=293(2)°K, R-0.036, Rta= 0.089, S= 0.849, F(000)= 255. IVC19H15NO2 kristali hemen hemen düzlemseldir. C=N bağıyla birbirine bağlı aromatik naftalin ve benzen halka düzlemleri arasındaki açı 1 0.98(4)°' dir. Kristal yapı naftaldiminlerde yaygın olarak gözlenen tautomerik formlardan keto-amin toutomerik formdadır. Molekül içi, bağ uzunluğu 2.5383(17)Â olan N-H...0 tipi kuvvetli bir hidrojen bağına sahiptir. Anahtar Kelime: o-Hidroksi Schiff bazları, Tautomeri, Fotokromizm, Salisilaldehit.
ABSTRACT In this study, crystal structures of 3-(4-Acetylphenyliminomethy)-l, 2- dihydroxy-benzen (C 1 5H 1 3NO3), 1 - {4-[(2-hydroxy-ben2ylidene)amino]phenyl }ethanone (C15H13NO2) and l-[4-Acetylphenylamino)-naphthalen-2(lH)-one (C19H15NO2) have been determined by x-ray diffraction method. Atomic parameters were refined by least squares and Fourier teqniques. C15Hi3N03, Monoclinic, P2,/c, a=l 0.001 4(1 1)Â, b=14.4188(14)Â, c=8.8212(10)Â, a= 90°, p=104.413(9)°, y=90°, V=1232.1(2)Â3, Z=4, Bx=1.376gr/cm3, X(MoKa)=0.71073Â, uHXlOmm'1, T=293(2)°K, R=0.035, Rco=0.086, S=0.092, F(000)=224. The crystal of C15H13NO3 is not planar and the dihedral angle between the planes of the two aromatic rings is 53.93(7)°. The N=C bond length of 1.271(2)A indicates it's double bond character. The phenol-imine tautomeric form is dominant in salicylaldimine schiff base. According to this, phenol-imine form is dominant in this crystal with two intramolecular O-H...N and O-H...O type and one intermolecular O- H...O type hydrogen bonds. C15H,3N02, Monoclinic, P2ı/c, a=14.7692(ll)Â, b=7.4051(5)Â, c=11.5752(14)Â, a=90°, p=l 06.898(8)°, y=90°, V=l 211. 29(1 9)Â3, Z=4, Dx=1.312gr/cm3, X(MoKa)=0.71073A, ^i=0.09mm'1, T=293(2)°K, R=0.038, Rco=0.100, S=0.097, F(000)=215. In the cyrstal of C15H13NO2, the dihedral angle between the planes of aromatic rings is 35.60(5)°. The bond lenght between the C and N atoms is 1.277(2)Â which indicates high degree double bond character. Cyrstal has only one intramolecular O- H...N type hydrogen bond with the bond length 2.5941 (15)Â. The phenol-imine tautomeric form is also dominant in this crystal. Ci9Hi5N02, Monoclinic, P2ı/c, a=6.7815(14)Â, b=14.0948(12)A, c=l 5.0855(1 0)Â, a=90°, p=90.050(5)°, y=90°, V=1441.93(2)Â3, Z=4, Dx=1.33gr/cm3, X(MoKa)=0.71073Â, u=0.087mm'1, T=293(2)°K, R=0.036, Rco=0.089, S=0.849, F(000)=255. VIThe crystal of C19H15NO2 is nearly planar with the dihedral angle of 10.98(4)° between the planes of naphthaline and benzen rings. It is believed that, the phenol-imine tautomeric form is dominant in salicylaldimine, while keto-amine form is dominant in ortho-hydroxynaphthaldimine schiff base. According to this idea, keto-amine tautomeric form is dominant in this structure with the intramolecular N-H...0 type hydrogen bond. The length of this bond is 2.5383(1 7)Â. Key word: o-Hydroxy Schiff Bases, Tautomerism, Fotochromism, Salicylaldimine. Vll
ABSTRACT In this study, crystal structures of 3-(4-Acetylphenyliminomethy)-l, 2- dihydroxy-benzen (C 1 5H 1 3NO3), 1 - {4-[(2-hydroxy-ben2ylidene)amino]phenyl }ethanone (C15H13NO2) and l-[4-Acetylphenylamino)-naphthalen-2(lH)-one (C19H15NO2) have been determined by x-ray diffraction method. Atomic parameters were refined by least squares and Fourier teqniques. C15Hi3N03, Monoclinic, P2,/c, a=l 0.001 4(1 1)Â, b=14.4188(14)Â, c=8.8212(10)Â, a= 90°, p=104.413(9)°, y=90°, V=1232.1(2)Â3, Z=4, Bx=1.376gr/cm3, X(MoKa)=0.71073Â, uHXlOmm'1, T=293(2)°K, R=0.035, Rco=0.086, S=0.092, F(000)=224. The crystal of C15H13NO3 is not planar and the dihedral angle between the planes of the two aromatic rings is 53.93(7)°. The N=C bond length of 1.271(2)A indicates it's double bond character. The phenol-imine tautomeric form is dominant in salicylaldimine schiff base. According to this, phenol-imine form is dominant in this crystal with two intramolecular O-H...N and O-H...O type and one intermolecular O- H...O type hydrogen bonds. C15H,3N02, Monoclinic, P2ı/c, a=14.7692(ll)Â, b=7.4051(5)Â, c=11.5752(14)Â, a=90°, p=l 06.898(8)°, y=90°, V=l 211. 29(1 9)Â3, Z=4, Dx=1.312gr/cm3, X(MoKa)=0.71073A, ^i=0.09mm'1, T=293(2)°K, R=0.038, Rco=0.100, S=0.097, F(000)=215. In the cyrstal of C15H13NO2, the dihedral angle between the planes of aromatic rings is 35.60(5)°. The bond lenght between the C and N atoms is 1.277(2)Â which indicates high degree double bond character. Cyrstal has only one intramolecular O- H...N type hydrogen bond with the bond length 2.5941 (15)Â. The phenol-imine tautomeric form is also dominant in this crystal. Ci9Hi5N02, Monoclinic, P2ı/c, a=6.7815(14)Â, b=14.0948(12)A, c=l 5.0855(1 0)Â, a=90°, p=90.050(5)°, y=90°, V=1441.93(2)Â3, Z=4, Dx=1.33gr/cm3, X(MoKa)=0.71073Â, u=0.087mm'1, T=293(2)°K, R=0.036, Rco=0.089, S=0.849, F(000)=255. VIThe crystal of C19H15NO2 is nearly planar with the dihedral angle of 10.98(4)° between the planes of naphthaline and benzen rings. It is believed that, the phenol-imine tautomeric form is dominant in salicylaldimine, while keto-amine form is dominant in ortho-hydroxynaphthaldimine schiff base. According to this idea, keto-amine tautomeric form is dominant in this structure with the intramolecular N-H...0 type hydrogen bond. The length of this bond is 2.5383(1 7)Â. Key word: o-Hydroxy Schiff Bases, Tautomerism, Fotochromism, Salicylaldimine. Vll
Description
Citation
WoS Q
Scopus Q
Source
Volume
Issue
Start Page
End Page
73
