3-Methoxy-2-[(E)-(4-methoxyphenyl)iminomethyl]phenol

Abstract

The title compound, C15H15NO3, adopts the enol-imine tautomeric form. The two rings are twisted with respect to each other, making a dihedral angle of 44.08 (5)degrees. The 3-methoxy-2-[(E)-(4-methoxyphenyl)-iminomethyl]phenol unit is almost planar, the largest deviation from the mean plane being 0.047 (2) angstrom. Such a planar conformation might be related to the occurrence of an intramolecular O-H center dot center dot center dot N hydrogen bond. In the crystal, intermolecular C-H center dot center dot center dot O hydrogen bonds link the molecules into sheets parallel to (010). These sheets are interconnected by weak C-H center dot center dot center dot pi interactions.